Among the given pairs,in which pair does the | vedclass

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(B) The boiling point of a compound depends on its molecular weight and intermolecular forces. In option $B$,$CH_3-CH_2-CH_2-CH_3$ (Butane) has a high

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$CH_3-CH_2-CH_2-CH_3$ and $CH_3-CH_2-CH_3$

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(B) The boiling point of a compound depends on its molecular weight and intermolecular forces. In option $B$,$CH_3-CH_2-CH_2-CH_3$ (Butane) has a higher molecular weight than $CH_3-CH_2-CH_3$ (Propane),leading to stronger London dispersion forces and a higher boiling point. In option $A$,the second compound $(CH_3-CH(OH)-CH_3)$ can form hydrogen bonds,whereas the first $(CH_3-CH_2-O-CH_3)$ cannot,so the second has a higher boiling point. In option $C$,the second compound is an alcohol,which has higher boiling points due to hydrogen bonding compared to the alkane. In option $D$,the second compound $(CH_3-CH_2-CH_2-Cl)$ has a higher molecular weight and dipole-dipole interactions compared to the alkane,resulting in a higher boiling point.

Among the given pairs,in which pair does the first compound have a higher boiling point than the second?

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